56b^2=14

Solution for 56b^2=14 equation:

56b^2=14

We move all terms to the left:

56b^2-(14)=0

a = 56; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·56·(-14)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*56}=\frac{-56}{112}
=-1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*56}=\frac{56}{112}
=1/2
$